Zion Williamson's Contract With Jordan Brand is Largest Rookie Shoe Deal in NBA History

New Orleans Pelicans rookie Zion Williamson has been the talk of the NBA offseason. After being selected first overall in the NBA Draft, Williamson reached an agreement with Jordan Brand on a shoe endorsement deal.

To say Williamson secured the bag is a massive understatement.

According to Action Network's Darren Rovell, Williamson's contract with Jordan Brand is for five-years and worth $75 million, which is the largest for a rookie in NBA history.

At five years, $75 million, Zion Williamson’s contract is among the highest guaranteed contracts Nike has handed out. MJ, LeBron, KD and Ronaldo among others that are bigger.
— Darren Rovell (@darrenrovell) July 24, 2019

LeBron James previously held the record when signing with Nike in 2003, where he earned an annual salary of $12.4 million over seven years. Williamson blows the annual wage out of the water with $15 million in the next five years.

After Williamson announced his decision through his Instagram account, NBA insider Adrian Wojnarowski revealed that several shoe companies offered larger sums of money than Jordan Brand.

ESPN Sources: The endorsement agreement aligning No. 1 overall pick Zion Williamson and Jordan Brand extends five years and becomes the richest annual rookie shoe deal in NBA history. Story: https://t.co/uQx8EdT0ur
— Adrian Wojnarowski (@wojespn) July 24, 2019

Despite the ridiculous amount of money left on the table, Williamson chose to wear the logo of his favorite player growing up.

Even with the discount, Williamson owns the richest rookie shoe deal in the history of the NBA, which is mind-boggling.